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zar88
@zar88
July 2022
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Помогите умоляю даю 15 баллов.. Найдите наибольшее и наименьшее значение функции f(x) = x^4 – 8x^2 -9 на отрезках (-1; 1), (0; 3).
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Answers & Comments
zarembo73
F(x)=x^4-8x²-9; (-1;1); (0;3)
f'(x)=(x^4-8x²-9)'=4x³-16x;
4x³-16x=0;
4x(x²-4)=0;
x=0
или
x²-4=0;
x=+-2.
(-1;1): -1; 0; 1.
f(-1)=(-1)^4-8*(-1)²-9=1-8-9=-16; - min
f(0)=0^4-8*0²-9=-9; - max
f(1)=1^4-8*1²-9=1-8-9=-16. - min
(0;3): 0; 2; 3.
f(0)=-9;
f(2)=2^4-8*2²-9=16-32-9=-25; - min
f(3)=3^4-8*3²-9=81-72-9=0. - max
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Answers & Comments
f'(x)=(x^4-8x²-9)'=4x³-16x;
4x³-16x=0;
4x(x²-4)=0;
x=0
или
x²-4=0;
x=+-2.
(-1;1): -1; 0; 1.
f(-1)=(-1)^4-8*(-1)²-9=1-8-9=-16; - min
f(0)=0^4-8*0²-9=-9; - max
f(1)=1^4-8*1²-9=1-8-9=-16. - min
(0;3): 0; 2; 3.
f(0)=-9;
f(2)=2^4-8*2²-9=16-32-9=-25; - min
f(3)=3^4-8*3²-9=81-72-9=0. - max