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grishinalarisa
@grishinalarisa
November 2021
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Найдите наименьшее возможное значение выражения: -3cos²х -6sinх + 11
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Удачник66
Verified answer
-3cos^2 x - 6sin x + 11 = -3 + 3sin^2 x - 6sin x + 11 =
= 3sin^2 x - 6sin x + 8 = 3sin^2 x - 6sin x + 3 + 5 = 3(sin x - 1)^2 + 5
Минимальное значение равно 5 при
sin x = 1; x = pi/2 + 2pi*k
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Answers & Comments
Verified answer
-3cos^2 x - 6sin x + 11 = -3 + 3sin^2 x - 6sin x + 11 == 3sin^2 x - 6sin x + 8 = 3sin^2 x - 6sin x + 3 + 5 = 3(sin x - 1)^2 + 5
Минимальное значение равно 5 при
sin x = 1; x = pi/2 + 2pi*k