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grishinalarisa
@grishinalarisa
November 2021
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Найдите наименьшее возможное значение выражения: -3cos²х – 6sinх +11
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sangers1959
Verified answer
Y=-3cos²-6sinx+11
y`=6sinxcosx-6cosx=0
6cosx(sinx-1)=0
cosx=0 x=π/2+πn
sinx=1 x=π/2+2πn
ymin=-3*0²-6*1+11=5.
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Answers & Comments
Verified answer
Y=-3cos²-6sinx+11y`=6sinxcosx-6cosx=0
6cosx(sinx-1)=0
cosx=0 x=π/2+πn
sinx=1 x=π/2+2πn
ymin=-3*0²-6*1+11=5.