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dimanux20nnnn
@dimanux20nnnn
July 2022
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найдите производную функции у=2(х^3+sin x )
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sangers1959
Verified answer
Y=2*(x³+sinx)
y`=2*(x³+sinx)`=2*(3x²+cosx)=6x²+2cosx.
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CTYDEHT34
Y'=(3x^2+cosx) вот производная
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Answers & Comments
Verified answer
Y=2*(x³+sinx)y`=2*(x³+sinx)`=2*(3x²+cosx)=6x²+2cosx.