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dimanux20nnnn
@dimanux20nnnn
July 2022
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вычислите наибольшее значение функции f(x)=x^3-x^2 на промежутке [-1;3]
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fainamakarova96
F'=(x^3)'-(x^2)'=3x^2-2x
f (-1)=3*(-1)^2-2*(-1)=3+2=5
f (3)=3*(3)^2-2*3=27-6=21
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fainamakarova96
Там на фотке ошибкп
dimanux20nnnn
у тебя ошибка
dimanux20nnnn
варианты ответа 2 4 0 9 -9 -4
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Answers & Comments
f (-1)=3*(-1)^2-2*(-1)=3+2=5
f (3)=3*(3)^2-2*3=27-6=21