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1i1kuz
@1i1kuz
July 2022
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Найдите точку пересечения прямых:
3у - ( х + 2 ) + 3 = 0 и 2 ( х - 3 ) + у + 4 = 0
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Universalka
Verified answer
3y - (x + 2) + 3 = 0 2(x - 3) + y + 4 = 0
3y = x + 2 - 3 y = - 4 - 2(x - 3)
3y = x - 1 y = - 4 - 2x + 6
y = - 2x + 2
Прямые пересекаются в точке с координатами (1 , 0)
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Answers & Comments
Verified answer
3y - (x + 2) + 3 = 0 2(x - 3) + y + 4 = 03y = x + 2 - 3 y = - 4 - 2(x - 3)
3y = x - 1 y = - 4 - 2x + 6
y = - 2x + 2
Прямые пересекаются в точке с координатами (1 , 0)