Найдите все значения х,при которых выполняется равенство
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nKrynka
Решение f`(x) = 2cos2x - √3 2cos2x - √3 = 0 2cos2x = √3 cos2x = √3/2 2x = +-arccos(√3/2) + 2πk, k ∈ Z 2x = +-(π/6) + 2πk, k ∈ Z x = +-(π/12) + πk, k ∈ Z x = π/12 + πk, k ∈ Z ; x ∈ [0;4π]
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f`(x) = 2cos2x - √3
2cos2x - √3 = 0
2cos2x = √3
cos2x = √3/2
2x = +-arccos(√3/2) + 2πk, k ∈ Z
2x = +-(π/6) + 2πk, k ∈ Z
x = +-(π/12) + πk, k ∈ Z
x = π/12 + πk, k ∈ Z ; x ∈ [0;4π]