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rarararara5
@rarararara5
June 2022
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Найдите значение a(в степени3)−b(в степени3), если известно, что a−b=0,7, а a(в степени2)b+ab−ab(в степени2)=13,6.
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Verified answer
A - b = 0,7
a^2*b + ab - ab^2 = ab*(a-b+1) = ab*(0,7+1) = 1,7ab = 13,6
ab = 13,6 / 1,7 = 136/17 = 8
a^3 - b^3 = (a-b)(a^2+ab+b^2) = (a-b)(a^2-2ab+b^2+3ab) =
= (a-b)((a-b)^2+3ab) = 0,7*(0,7^2+3*8) = 0,7*(0,49+24) = 17,143
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Verified answer
A - b = 0,7a^2*b + ab - ab^2 = ab*(a-b+1) = ab*(0,7+1) = 1,7ab = 13,6
ab = 13,6 / 1,7 = 136/17 = 8
a^3 - b^3 = (a-b)(a^2+ab+b^2) = (a-b)(a^2-2ab+b^2+3ab) =
= (a-b)((a-b)^2+3ab) = 0,7*(0,7^2+3*8) = 0,7*(0,49+24) = 17,143