Найти производную функции:
f(x)=((x-3)^3)*(x-1)
f(x)=((x^2)-9)*(x+1)
f(x)=(x-3)³ (x-1)
f'(x)=((x-3)³)' (x-1) + (x-1)' (x-3)³ = 3(x-3)²(x-1)+ 1*(x-3)³=(x-3)²(3(x-1)+ (x-3))=
=(x-3)²(3x-3+ x-3)= (x-3)²(4x-6)= 2(2x-3)(x-3)²
f(x)=(x²-9) (x+1)
f'(x)=(x²-9)' (x+1)+ (x+1)' (x²-9) = 2x(x+1)+ 1*(x²-9) = 2x²+2x+x²-9 = 3x²+2x-9
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Answers & Comments
f(x)=(x-3)³ (x-1)
f'(x)=((x-3)³)' (x-1) + (x-1)' (x-3)³ = 3(x-3)²(x-1)+ 1*(x-3)³=(x-3)²(3(x-1)+ (x-3))=
=(x-3)²(3x-3+ x-3)= (x-3)²(4x-6)= 2(2x-3)(x-3)²
f(x)=(x²-9) (x+1)
f'(x)=(x²-9)' (x+1)+ (x+1)' (x²-9) = 2x(x+1)+ 1*(x²-9) = 2x²+2x+x²-9 = 3x²+2x-9
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