Продифференцировать функцию:
6(x^2)+5x-7
(6x^2+5x-7)'=(6x^2)'+(5x)'-(7)'=6(x^2)'+5(x)'+0=6*2x+5*1=12x+5
(6x²+5x-7)' = (6x²)' + (5x)' - (7)' = 12x + 5 - 0 = 12x + 5
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
(6x^2+5x-7)'=(6x^2)'+(5x)'-(7)'=6(x^2)'+5(x)'+0=6*2x+5*1=12x+5
Verified answer
(6x²+5x-7)' = (6x²)' + (5x)' - (7)' = 12x + 5 - 0 = 12x + 5