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Lantica
@Lantica
July 2022
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sedinalana
Verified answer
(tga-ctga)/(tga+ctga)=(sina/cosa-cosa/sina):(sina/cosa+cosa/sina)=
=(sin²a-cos²a)/(sinacosa) :(sin²a+cos²a)/(sinacosa)=
-cos2a/(sinacosa)*(sinacosa)/1=-cos2a
1 votes
Thanks 1
mmb1
Verified answer
Tg = sin / cos
ctg = cos / sin
cos² x - sin² x = cos (2x)
sin² x + cos² x = 1
tg(a) - ctg(a) = sin(a)/cos(a) - cos(a)/sin(a) = (sin²(a) - cos²(a))/sin(a)cos(a)= - cos(2x)/sin(a)cos(a)
tg(a) + ctg(a) = sin(a)/cos(a) + cos(a)/sin(a) = (sin²(a) + cos²(a))/sin(a)cos(a)= 1 /sin(a)cos(a)
- cos(2x)/sin(a)cos(a) / 1 /sin(a)cos(a) = - cos(2x)/sin(a)cos(a) * sin(a)cos(a)/1 = -cos(2a)
2 votes
Thanks 1
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Answers & Comments
Verified answer
(tga-ctga)/(tga+ctga)=(sina/cosa-cosa/sina):(sina/cosa+cosa/sina)==(sin²a-cos²a)/(sinacosa) :(sin²a+cos²a)/(sinacosa)=
-cos2a/(sinacosa)*(sinacosa)/1=-cos2a
Verified answer
Tg = sin / cosctg = cos / sin
cos² x - sin² x = cos (2x)
sin² x + cos² x = 1
tg(a) - ctg(a) = sin(a)/cos(a) - cos(a)/sin(a) = (sin²(a) - cos²(a))/sin(a)cos(a)= - cos(2x)/sin(a)cos(a)
tg(a) + ctg(a) = sin(a)/cos(a) + cos(a)/sin(a) = (sin²(a) + cos²(a))/sin(a)cos(a)= 1 /sin(a)cos(a)
- cos(2x)/sin(a)cos(a) / 1 /sin(a)cos(a) = - cos(2x)/sin(a)cos(a) * sin(a)cos(a)/1 = -cos(2a)