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shpont
@shpont
July 2022
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Очень срочно!!!Решите пож-та 4,5,6 задания..
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kirichekov
Verified answer
Решение во вложении----------------
2 votes
Thanks 0
VictoriaVl
6. a) cos(π+x)=sin(π\2)
cos(π+x)=1
π+x=2πk, k∈Ζ
x=π(2k-1), k∈Ζ
b) cos²x-√3 sinx cosx=0 |÷cos²x
1-√3 tgx=0
tgx=√3/3
x=π/6+πk, k∈Ζ
1 votes
Thanks 1
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Answers & Comments
Verified answer
Решение во вложении----------------cos(π+x)=1
π+x=2πk, k∈Ζ
x=π(2k-1), k∈Ζ
b) cos²x-√3 sinx cosx=0 |÷cos²x
1-√3 tgx=0
tgx=√3/3
x=π/6+πk, k∈Ζ