Verified answer

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Verified answer

Дана систему уравнений

{2^x+3^y=17

{2^x-3^y=15 сложим 2 уравнения:

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2*2^x = 32

2^(x+1) = 2^5

x+ 1 = 5

x = 5 - 1 = 4.

3^y = 17  - 2^x = 17 - 16 = 1 = 3^0.

y = 0.

Ответ: х = 4, у = 0.