помогите!!! если лень решать, натолкните хотя бы на мысль . Created by ksenia123tea. algebra-ru

помогите!!! если лень решать, натолкните хотя бы на мысль ...

ksenia123tea @ksenia123tea

August 2022 1 15 Report

помогите!!! если лень решать, натолкните хотя бы на мысль

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Verified answer

$6Sin^{2} 40^{0} -6Cos^{2}40^{0}+3\sqrt{3}Cos50^{0} -3Sin50^{0}=\\\\=-6(Cos^{2}40^{0}-Sin^{2}40^{0}) +3(\sqrt{3}Cos50^{0}-Sin50^{0})=\\\\=-6Cos80^{0}+3*2(\frac{\sqrt{3} }{2}Cos50^{0}-\frac{1}{2}Sin50^{0})=$

$=-6Cos80^{0}+6(Cos30^{0}Cos50^{0}-Sin30^{0}Sin50^{0})=\\\\=-6Cos80^{0} +6Cos(30^{0}+50^{0})=-6Cos80^{0}+6Cos80^{0}=\boxed0$

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Verified answer

pomnite esli len reshat natolknite hotya by na mysl

pomogite esli len reshat natolknite hotya by na myslcbee9fcd5cbf4bb382b4cc06083ffe2e 8995

pomogite esli len reshat natolknite hotya by na mysla97725ee97146547252a6ebb70800adc 81871

pomogite esli len reshat natolknite hotya by na mysld2cd77c9f4d604e6658fccabb2ecaa59 98153

pomogite pozhalujsta s resheniem hotya by kratkim5ddc357b4201a11d25d7c5dcb53101d1 67499

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pomogite pozhalujsta esli len reshat natolknite hotya by na myslbf0ec9ff79ea022d0ce6657ee8bb9472 37331

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