Помогите решить алгоритм Log2log11(5^x-4)

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Помогите решить алгоритм Log2log11(5^x-4)<1

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$log_2(log_{11}(5^x-4))\ \textless \ 1$
Область определения
5^x - 4 > 0; 5^x > 4; x > log5(4)
$log_{11}(5^x-4)\ \textgreater \ 0$
$5^x-4\ \textgreater \ 1$

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Удачник66 Дайте отредактировать или удалите этот ответ!

Удачник66 ОДЗ 5^x>5; x>1

Удачник66 Решение log11(5^x-4)<2; 5^x-4<121; 5^x<125; x<3

Удачник66 Ответ 1<х<3

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Answers & Comments

Verified answer

1najdite proizvedenie kornejkorenesli on edinstvennyjx2 x x1x 215417f058e3dfc93d0ada236c1145261ae 12986

razlozhite na mnozhiteli 117x 34 29a2 x 3x 37x2y3 21xy4 4a2 6a9 y2 5y

srochno pomogite s 136 i 138 zadachej smotrite risunok

summa pervyh 80 chlenov arifmeticheskoj progressii ravna 80 a summa pervyh 160 ee

summa pervyh 10 chlenov arifmeticheskoj progressii ravna 5a summa pervyh 40 ee chl

perevedite pozhalujsta tolko ne s perevodchika ochen nuzhno zaranee spasibo tekst

1najdite proizvedenie kornejkorenesli on edinstvennyjx2 x x1x 215

pomogite srochno reshit a30 i v 34 smotrite vlozheniya

najdite kolichestvo vseh celyh znachenij neravenstva 64x x3 eto vse delit na 5x

v treugolnike abc mediany an i cm peresekayutsya pod pryamym uglomnajdite mn esli

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