Помогите решить пожалуйста!!!!!!!!!!!!!!!!!. Created by unique2. algebra-ru

Помогите решить пожалуйста!!!!!!!!!!!!!!!!!...

unique2 @unique2

August 2022 1 11 Report

Помогите решить пожалуйста!!!!!!!!!!!!!!!!!

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sedinalana

Verified answer

[(3/5)²]^[(x-3)/2x]≥√(3/5)
(3/5)^[(x-3)/x]≥√(3/5)
(x-3)/x≤1/2
(x-3)/x-1/2≤0
(2x-6-x)/(2x)≤0
(x-6)/x≤0
x=6 x=0
+ _ +
----------------(0)---------------------[6]---------------
x∈(0;6]

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unique2 August 2022 | 0 Ответы

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unique2 August 2022 | 0 Ответы

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Answer

unique2 July 2022 | 0 Ответы

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Answer

Answers & Comments

Verified answer

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