Помогите решить, пожалуйста! sqrt(х^2+3х+3)< 2x+1. Created by JevelS. algebra-ru

Помогите решить, пожалуйста! sqrt(х^2+3х+3)< 2x+1...

JevelS @JevelS

June 2021 1 20 Report

Помогите решить, пожалуйста! sqrt(х^2+3х+3)< 2x+1

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NNNLLL54

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ОДЗ: $x^2+3x+3 \geq 0\\2x+1 \geq 0$
$D=9-12=-30\;\; pri\;x\in R\\2x+1> 0,\;x > -\frac{1}{2}$
$x^2+3x+30\\x_1=-1,x_2=\frac{2}{3}\\x\in (-\infty,-1)U(\frac{2}{3},+\infty)
\\Otvet:\;x\in (\frac{2}{3},+\infty)$

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