Помогите решить, пожалуйста! sqrt(х^2+3х+3)< 2x+1. Created by JevelS. algebra-ru

Помогите решить, пожалуйста! sqrt(х^2+3х+3)< 2x+1...

JevelS @JevelS

June 2021 1 22 Report

Помогите решить, пожалуйста! sqrt(х^2+3х+3)< 2x+1

Answers & Comments

NNNLLL54

Verified answer

ОДЗ: $x^2+3x+3 \geq 0\\2x+1 \geq 0$
$D=9-12=-30\;\; pri\;x\in R\\2x+1> 0,\;x > -\frac{1}{2}$
$x^2+3x+30\\x_1=-1,x_2=\frac{2}{3}\\x\in (-\infty,-1)U(\frac{2}{3},+\infty)
\\Otvet:\;x\in (\frac{2}{3},+\infty)$

2 votes Thanks 1

pomogite plz cherez seredinu naibolshej storony treugolnika provedena pryamaya2b6792bbab62e97238a821dfc12b82f1 7120

Answer

JevelS August 2022 | 0 Ответы

pomogite reshit budu preochen blagodarna kto pravilno reshit otmechu kak luch

Answer

JevelS August 2022 | 0 Ответы

dokazhite chto srednyaya liniya delit popolam diagonal trapecii

Answer

JevelS August 2022 | 0 Ответы

kakimi predlozheniyami mozhno sostavit vyvod v laboratornoj rabote na temu osanka

Answer

JevelS August 2022 | 0 Ответы

pomogite pozhalujsta na otrezke soedinyayushem serediny osnovanij ad i dc trapecii

Answer

Answers & Comments

Verified answer

pomogite plz cherez seredinu naibolshej storony treugolnika provedena pryamaya2b6792bbab62e97238a821dfc12b82f1 7120

pomogite reshit budu preochen blagodarna kto pravilno reshit otmechu kak luch

dokazhite chto srednyaya liniya delit popolam diagonal trapecii

kakimi predlozheniyami mozhno sostavit vyvod v laboratornoj rabote na temu osanka

prishla s ekzamena ne uverena v reshenii etogo zadaniya pomogite pozhalujsta

pomogite srochno katushka iz mednoj provoloki imeet soprotivlenie r 108om mas

pomogite pozhalujsta v treugolnike abc ab8v2 ac18 ugol a45 gradusam

pomogite pozhalujsta vershiny treugolnika avs lezhat na okruzhnosti avvs23

pomogite pozhalujsta v trapecii provedeny diagonali ploshadi dvuh treugolnikov

pomogite pozhalujsta na otrezke soedinyayushem serediny osnovanij ad i dc trapecii

рекомендуемые вопросы

Helpful Links

Helpful Social