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mona76
@mona76
July 2022
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Помогите решить, решение показать обязательно:
cos 2x + cos 4x - cos 3x = 0
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sedinalana
Verified answer
2сos3xcosx-cos3x=0
cos3x*(2cosx-1)=0
cos3x=0⇒3x=π/2+πn⇒x=π/6+πn/3,n∈z
cosx=1/2⇒x=+-π/3+2πn,n∈z
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Verified answer
2сos3xcosx-cos3x=0cos3x*(2cosx-1)=0
cos3x=0⇒3x=π/2+πn⇒x=π/6+πn/3,n∈z
cosx=1/2⇒x=+-π/3+2πn,n∈z