Помогите решить задачу!!!. Created by bashmak1997. fizika-ru

Помогите решить задачу!!!...

Nasty2121 F=k/e*q1*q2/r^2=m1a1=m2a2
m1=m2=m
a1=a2=a=F/m=k/e*q1*q2/(r^2*m)=8,99*10^9/20*100*10^(-9)*200*10^(-9)/(0,2^2*0,0002)=
=1,12375 м/с2 ~1,1 м/с2

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1 Найти силу взаимодействия F = k*g1*g2/20*R^2=9*10^9*10^-7*2*10^-7/20*0,04.....
2 Найдем проекцию ускорения а= F/m=.......

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