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Shutilova
@Shutilova
September 2021
1
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Помогите со вторым, пожалуйста, у меня не выходит
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oganesbagoyan
Verified answer
1)
По теореме косинусов:
AB²=BC²+AC²-2*BC*AC*cosC ;
AB²=(4√3)²+8²-2*4√(3) *8*cos30° =48+64 - 64*√(3)*√(3)/2 =112 -96 =16 =4²..
AB =4 .
2)
По теореме синусов:
AC/sinB =BC/sinA ;
AC = BC *sinB/sinA;
AC
=10*sin(180° -60°)/sin45° =10*sin60°/sin45° =10*(√3)/2
/ (
√2)/2 =10√3 / √2 =
5√6.
2 votes
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Answers & Comments
Verified answer
1) По теореме косинусов:AB²=BC²+AC²-2*BC*AC*cosC ;
AB²=(4√3)²+8²-2*4√(3) *8*cos30° =48+64 - 64*√(3)*√(3)/2 =112 -96 =16 =4²..
AB =4 .
2) По теореме синусов:
AC/sinB =BC/sinA ;
AC = BC *sinB/sinA;
AC =10*sin(180° -60°)/sin45° =10*sin60°/sin45° =10*(√3)/2 / (√2)/2 =10√3 / √2 =5√6.