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Shutilova
@Shutilova
July 2022
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Сколько атомов содержится в 160г меди?
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evgenykvetkin
N(Cu) = n(Cu) * N(Авогадро)
n(Cu) = 160г :64 г/моль = 2.5 моль
N(Cu) = 2.5 * 6.02*10²³ = 15.05*10²³атомов
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Answers & Comments
n(Cu) = 160г :64 г/моль = 2.5 моль
N(Cu) = 2.5 * 6.02*10²³ = 15.05*10²³атомов