fe3o4+3h2=2fe+3h2o
m(fe)=14 г
n(fe)= 14/56=0.25 моль
=> n(h2)=0.375 моль по реакции
V(h2)= 0.375*22.4=8.4 дм3
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
fe3o4+3h2=2fe+3h2o
m(fe)=14 г
n(fe)= 14/56=0.25 моль
=> n(h2)=0.375 моль по реакции
V(h2)= 0.375*22.4=8.4 дм3