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VOLKOVA2013
@VOLKOVA2013
July 2022
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решение производных первые 4
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Kim1205
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1)f'(x)=(8*x^4-1/x^2+x*корень (x)-2)=32*x^3+2/x^3+корень(х)+х/2*корень(х)
2)f'(x)=(корень(х)*(4*х-3))=(4*х-3)/2*корень(х)+4*корень(х)
3)f'(х)=((1+3*х^2)/(1-3*x^2))=6*x-18*x^3+6*x+18*x^3=12*x
4)f'(x)=10*(1-4*x^2)^9
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Kim1205
3)12*x/(1-3*x^2)
Kim1205
3)12*x/(1-3*x^2)^2
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Answers & Comments
Verified answer
1)f'(x)=(8*x^4-1/x^2+x*корень (x)-2)=32*x^3+2/x^3+корень(х)+х/2*корень(х)2)f'(x)=(корень(х)*(4*х-3))=(4*х-3)/2*корень(х)+4*корень(х)
3)f'(х)=((1+3*х^2)/(1-3*x^2))=6*x-18*x^3+6*x+18*x^3=12*x
4)f'(x)=10*(1-4*x^2)^9