Решить 25&and;х +2*а*5&and;х +а&and;2=0, -3 &ang; х ≤2. Created by rainanadia. algebra-ru

Решить 25∧х +2*а*5∧х +а∧2=0, -3 ∠ х ≤2...

July 2022 1 4 Report

Решить 25∧х +2*а*5∧х +а∧2=0, -3 ∠ х ≤2

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igundane

$25^x+2a\cdot 5^x+a^2=0\\5^{2x}+2a\cdot 5^x+a^2=0\\5^x=b,b>0\Rightarrow b^2+2ab+a^2=0\\(a+b)^2=0\Rightarrow a+b=0\\a=-b\Rightarrow a=-5^x\Rightarrow x=log_5(-a)$

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