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21032
@21032
August 2022
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решите 13 задание..........
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Lesben
6.sinˇ2 (x) +5. sin(pí/2 - x) -2=0
6.(1-cosˇ2 (x)) +5.cos x -2=0
6.cosˇ2 x - 5.cos x -4=0
cos x =t
6.tˇ2 -5.t -4 =0, t1=4/3, t2=-1/2
a)cos x = 4/3 nevozmožno, cos x ne možet bit bolše čem 1
b)cos x =-1/2
x=2pí/3+2k.pí i tože x = 4pí/3+2k.pí
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Answers & Comments
6.(1-cosˇ2 (x)) +5.cos x -2=0
6.cosˇ2 x - 5.cos x -4=0
cos x =t
6.tˇ2 -5.t -4 =0, t1=4/3, t2=-1/2
a)cos x = 4/3 nevozmožno, cos x ne možet bit bolše čem 1
b)cos x =-1/2
x=2pí/3+2k.pí i tože x = 4pí/3+2k.pí