Ответ:
Пошаговое объяснение:
10.
2cos40°cos20° - cos20° = cos(40°-20°)+cos(40°+20°) - cos20° = cos60° = 0,5
2sin40°sin10° + cos50° = cos30° - cos50° + cos50° = cos30° = √3/2
12.
0,5(sin6x-sin2x)-0,5(sin14x-sin2x)=0,5sin6x - 0,5sin14x =
=sin(-4x)cos20x = -sin(4x)cos(20x)
cos5xcosx - cos4xcos2x = 0,5(cos6x+cos4x) - 0,5(cos6x - cos2x) =
=0,5cos4x - 0,5cos2x = -sin(3x)sin(x)
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Verified answer
Ответ:
Пошаговое объяснение:
10.
2cos40°cos20° - cos20° = cos(40°-20°)+cos(40°+20°) - cos20° = cos60° = 0,5
2sin40°sin10° + cos50° = cos30° - cos50° + cos50° = cos30° = √3/2
12.
0,5(sin6x-sin2x)-0,5(sin14x-sin2x)=0,5sin6x - 0,5sin14x =
=sin(-4x)cos20x = -sin(4x)cos(20x)
cos5xcosx - cos4xcos2x = 0,5(cos6x+cos4x) - 0,5(cos6x - cos2x) =
=0,5cos4x - 0,5cos2x = -sin(3x)sin(x)