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45ghhh
@45ghhh
July 2022
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решите тригонометрическое уравнение
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Gerren
Sinx-√3cosx=
sinx-√3cosx=
sinx-√3cosx=
sinx-√3cosx=
sinx-√3cosx=2
1/2*sinx-√3/2*cosx=1
1/2=sin(pi/6)
√3/2=cos(pi/6)
sinx*sin(pi/6)-cosx*cos(pi/6)=1
cosx*cos(pi/6)-sinx*sin(pi/6)=-1
cos(x+pi/6)=-1
x+pi/6=pi+2pi*n n∈Z
x=5pi/6+2pi*n n∈Z
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Gerren
метод ввода дополнительного аргумента
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Answers & Comments
sinx-√3cosx=
sinx-√3cosx=
sinx-√3cosx=
sinx-√3cosx=2
1/2*sinx-√3/2*cosx=1
1/2=sin(pi/6)
√3/2=cos(pi/6)
sinx*sin(pi/6)-cosx*cos(pi/6)=1
cosx*cos(pi/6)-sinx*sin(pi/6)=-1
cos(x+pi/6)=-1
x+pi/6=pi+2pi*n n∈Z
x=5pi/6+2pi*n n∈Z