Решите уравнение: (x^2+x+1)(x^2+x+2)=12 Пожалуйста помогите!!! Срочно!!!. Created by tomiristoktam3. algebra-ru

(x²+x+1)(x²+x+2)=12Замена: t=x²+x(t+1)(t+2)=12t²+3t+2-12=0t²+3t-10=0по теореме Виета получаем:{t₁*t₂=-10{t₁+t₂=-3 => t₁=2; t₂=-5Обратная замена:x²+x=2 и x²+x=-5x²+x-2=0 x²+x+5=0по т. Виета D=1²-4*1*5=1-20=-19<0x₁=1; x₂=-2 корней нетОтвет: -2; 1 Новые вопросы в АлгебраПри якому значенні параметра а є розвязки 2(x-a)решите линейное уравнение4х+у=2 3х-2у=7 2х-5у=8яке допустиме значення підходить до дробу х—3/х^2+3Срочно. Допоможіть будь ласка №4. Доведіть, що при будь-якому натуральному n: 1) (5n+4)² - (5n-4)² кратне 80 2) (n² + n)(n+2) кратне 3 3) n³ - n кратне 6 4) 2n⁵ + 5n⁴ - 2n² - 5n кр…атне n3 - 1Розв’яжіть рівняння: 60/x - 60/(x+10)=1/53x/(x^2-10x+25) - (x-3)/(x^2)=1/xУстановіть відповідність між формулами якими задані функції та помножити їх областей визначення y=sin4x; y=✓5-xЗапишіть у вигляді многолена різницю квадратів виразів 3с і 5в Плиииииииз1){3х-2у=7 {2х+2у=8 .2) {7х-0,4у=-15 {4х-0,4у=10.3){5х-0,6у=-6…{2х-0,3у=16.В многочлен х3 - 3x² + 2х - 5 вместо переменной х подставьте данное выражение и запишите полученное выражение как многочлен стандартного вида: a) y +…5; б) 2у - 1; в) 3у + 4.ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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Решите уравнение: (x^2+x+1)(x^2+x+2)=12 Пожалуйста помогите!!! Срочно!!!...

tomiristoktam3 @tomiristoktam3

August 2022 1 5 Report

Решите уравнение:
(x^2+x+1)(x^2+x+2)=12
Пожалуйста помогите!!! Срочно!!!

Answers & Comments

Эксперт5

Verified answer

(x²+x+1)(x²+x+2)=12
Замена: t=x²+x
(t+1)(t+2)=12
t²+3t+2-12=0
t²+3t-10=0
по теореме Виета получаем:
{t₁*t₂=-10
{t₁+t₂=-3 => t₁=2; t₂=-5
Обратная замена:
x²+x=2 и x²+x=-5
x²+x-2=0 x²+x+5=0
по т. Виета D=1²-4*1*5=1-20=-19<0
x₁=1; x₂=-2 корней нет
Ответ: -2; 1