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tanyalyashchuk
@tanyalyashchuk
July 2022
1
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Розв'яжіть нерівності:
1.) (x-2)(2x-9)^2>0
2.) (9x^2-6x+1)(x-2)≥0
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sedinalana
Verified answer
1
(x-2)(2x-9)>0
x-2=0⇒x=2
2x-9=0⇒x=4,5
_ + +
---------------(2)-----------(4,5)---------------
x∈(2;4,5) U (4,5;∞)
2
(3x-1)²(x-2)≥0
3x-1=0⇒x=1/3
x-2=0⇒x=2
_ _ +
----------------[1/3]--------------[2]----------------------
x∈[2;∞) U {1/3}
1 votes
Thanks 0
tanyalyashchuk
Поясніть, будь ласка, принцип визначення даних проміжків
sedinalana
не понимаю
tanyalyashchuk
Объясните, пожалуйста, принцип определения данных промежутков
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Answers & Comments
Verified answer
1(x-2)(2x-9)>0
x-2=0⇒x=2
2x-9=0⇒x=4,5
_ + +
---------------(2)-----------(4,5)---------------
x∈(2;4,5) U (4,5;∞)
2
(3x-1)²(x-2)≥0
3x-1=0⇒x=1/3
x-2=0⇒x=2
_ _ +
----------------[1/3]--------------[2]----------------------
x∈[2;∞) U {1/3}