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kobzarenko99
@kobzarenko99
July 2021
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Сделать срочно даю 30 балов за 7 и 9 задание
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oganesbagoyan
Verified answer
7)
V =
120 см³ .
V₁ =(1/3)S₁*H =(1/3)(a*b/2)*H =(1/6)ab*H =(1/6)V = (1/6)*120 см³
=20 см³
.
→
Д
-------
9)
(если понял правильно)
S(ASC) = 120 см² , SO =H =15 см
.
---
V₁ =V(SNPKM) -?
a₁=NP =PK=KM =MN .
V₁ =(1/3)*S₁*H =(1/3)* a₁²*H = (1/3)*(d/2)²*H= (1/3)* (d/2)²*H ; || d =AC ||.
дано
S(ASC) = 120 см² ⇒ d*H/2 = 120 ⇒d =2*120/H =2*120/15 = 2*8 =16.
V₁
=(1/3)*(16/2)²*15 =5*8² =5*64
=320
(см³) .
ответ :320 см³
.
* * * NP =AC/2 свойство средней линии треугольника * * *
1 votes
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Answers & Comments
Verified answer
7) V = 120 см³ .V₁ =(1/3)S₁*H =(1/3)(a*b/2)*H =(1/6)ab*H =(1/6)V = (1/6)*120 см³ =20 см³.
→Д
-------
9) (если понял правильно) S(ASC) = 120 см² , SO =H =15 см.
---
V₁ =V(SNPKM) -?
a₁=NP =PK=KM =MN .
V₁ =(1/3)*S₁*H =(1/3)* a₁²*H = (1/3)*(d/2)²*H= (1/3)* (d/2)²*H ; || d =AC ||.
дано S(ASC) = 120 см² ⇒ d*H/2 = 120 ⇒d =2*120/H =2*120/15 = 2*8 =16.
V₁ =(1/3)*(16/2)²*15 =5*8² =5*64 =320 (см³) .
ответ :320 см³ .
* * * NP =AC/2 свойство средней линии треугольника * * *