Сделать срочно даю 40 балов за 4 задания с 17-20. Created by kobzarenko99. matematika-ru

17.x² /(x+2) < x /(x+2) ;x² /(x+2) - x/(x+2) <0 ;x(x-1)/(x+2) <0 ; - + - +///////////(-2) --------- (0)///////////// (1) ----------x∈( -∞; -2) U (0; 1)Д)---18.(x-2)√(x² -5x+4) =0 ;[ x² -5x+4=0 ; {x-2=0 , x² -5x+4 ≥0.⇔ [x² -5x+4 =0 ; { x∈∅.сумма корней будет 4. В)---19.d =√( (-8)² +6²) =√(64 +36) =√100 =10.А)---20.S =a²{ 2a² +h² =13² ; a² +h²=12².(где a сторона основания, h высота призмы ).⇒ (2a² +h²) -( a² +h²) =13² -12²⇔a² =25 . S =25 (см²).А)Новые вопросы в МатематикаЗнайдіть різницю векторів а (3; 1; -2) і b (3; -2; 5)Які координати має вектор MN, якщо NM= (2; -7; 4) ?Знайдіть довжину вектора MN, якщо M(3; 2; -1), N (1; -2; 1)Знайдіть модуль вектора а= (1; 2; 6)чим є геометричне місце точок простору, для яких дорівнює нулю...CO - перпендикуляр к прямой ОD, найдите <МОВ, если <МОА = <СОА = 20°, <ВОD = <МОВ. с объяснением плис:>a^2-b^2+a+bПомогитеПериметр ромба АВСD дорівнює 60 см. З вершини тупого кута В ромба до сторони AD проведено перпендикуляр ВК, КD = 6 см. 1. Знайдіть довжину перпендикул…яра ВК (у см) 2. Знайдіть площу ромба ABCD (у см²).Площа прямокутного трикутника дорівнює 60см2, а його гіпоненуза - 17см. Знайти більший катет трикутникаПомогите пожалуйста решить.ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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\u043d\u0443\u043b\u044e..."},{"id":49780921,"content":"CO - \u043f\u0435\u0440\u043f\u0435\u043d\u0434\u0438\u043a\u0443\u043b\u044f\u0440 \u043a \u043f\u0440\u044f\u043c\u043e\u0439 \u041eD, \u043d\u0430\u0439\u0434\u0438\u0442\u0435 <\u041c\u041e\u0412, \u0435\u0441\u043b\u0438 <\u041c\u041e\u0410 = <\u0421\u041e\u0410 = 20\u00b0, <\u0412\u041eD = <\u041c\u041e\u0412. \u0441 \u043e\u0431\u044a\u044f\u0441\u043d\u0435\u043d\u0438\u0435\u043c \u043f\u043b\u0438\u0441:>"},{"id":49780897,"content":"a^2-b^2+a+b\n\u041f\u043e\u043c\u043e\u0433\u0438\u0442\u0435"},{"id":49780883,"content":"\u041f\u0435\u0440\u0438\u043c\u0435\u0442\u0440 \u0440\u043e\u043c\u0431\u0430 \u0410\u0412\u0421D \u0434\u043e\u0440\u0456\u0432\u043d\u044e\u0454 60 \u0441\u043c. \u0417 \u0432\u0435\u0440\u0448\u0438\u043d\u0438 \u0442\u0443\u043f\u043e\u0433\u043e \u043a\u0443\u0442\u0430 \u0412 \u0440\u043e\u043c\u0431\u0430 \u0434\u043e \u0441\u0442\u043e\u0440\u043e\u043d\u0438 AD \u043f\u0440\u043e\u0432\u0435\u0434\u0435\u043d\u043e \u043f\u0435\u0440\u043f\u0435\u043d\u0434\u0438\u043a\u0443\u043b\u044f\u0440 \u0412\u041a, \u041aD = 6 \u0441\u043c. 1. \u0417\u043d\u0430\u0439\u0434\u0456\u0442\u044c \u0434\u043e\u0432\u0436\u0438\u043d\u0443 \u043f\u0435\u0440\u043f\u0435\u043d\u0434\u0438\u043a\u0443\u043b\u044f\u0440\u0430 \u0412\u041a (\u0443 \u0441\u043c) 2. \u0417\u043d\u0430\u0439\u0434\u0456\u0442\u044c \u043f\u043b\u043e\u0449\u0443 \u0440\u043e\u043c\u0431\u0430 ABCD (\u0443 \u0441\u043c\u00b2).\u200b"},{"id":49780882,"content":"\u041f\u043b\u043e\u0449\u0430 \u043f\u0440\u044f\u043c\u043e\u043a\u0443\u0442\u043d\u043e\u0433\u043e \u0442\u0440\u0438\u043a\u0443\u0442\u043d\u0438\u043a\u0430 \u0434\u043e\u0440\u0456\u0432\u043d\u044e\u0454 60\u0441\u043c2, \u0430 \u0439\u043e\u0433\u043e \u0433\u0456\u043f\u043e\u043d\u0435\u043d\u0443\u0437\u0430 - 17\u0441\u043c. \u0417\u043d\u0430\u0439\u0442\u0438 \u0431\u0456\u043b\u044c\u0448\u0438\u0439 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Сделать срочно даю 40 балов за 4 задания с 17-20...

kobzarenko99 @kobzarenko99

July 2022 1 11 Report

Сделать срочно даю 40 балов за 4 задания с 17-20

Answers & Comments

oganesbagoyan

Verified answer

17.
x² /(x+2) < x /(x+2) ;
x² /(x+2) - x/(x+2) <0 ;
x(x-1)/(x+2) <0 ;
- +    - +
///////////(-2) --------- (0)///////////// (1) ----------
x∈( -∞; -2) U (0; 1)
Д)
---
18.
(x-2)√(x² -5x+4) =0 ;
[ x² -5x+4=0 ;  {x-2=0 , x² -5x+4 ≥0.⇔ [x² -5x+4 =0 ; { x∈∅.
сумма корней будет 4.
В)
---
19.
d =√( (-8)² +6²) =√(64 +36) =√100 =10.
А)
---
20.
S =a²
{ 2a² +h² =13² ; a² +h²=12².(где a сторона основания, h высота призмы ).
⇒ (2a² +h²) -( a² +h²) =13² -12²⇔a² =25 . S =25 (см²).
А)