1)x^2−5x+4=0
Решение:
x^2-5x+4=x^2-4x-x+4=x(x-4)-(x-4)=(x-1)(x-4)x2−5x+4=x2−4x−x+4=x(x−4)−(x−4)=(x−1)(x−4)
x1=1 x2=-4
2)x^2−3x+2=0
Решение:x^2-3x+2=x^2-2x-x+2=x(x-2)-(x-2)=(x-1)(x-2)x 2−3x+2=x 2−2x−x+2=x(x−2)−(x−2)=(x−1)(x−2)
x1=1 x2=2
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
1)x^2−5x+4=0
Решение:
x^2-5x+4=x^2-4x-x+4=x(x-4)-(x-4)=(x-1)(x-4)x2−5x+4=x2−4x−x+4=x(x−4)−(x−4)=(x−1)(x−4)
x1=1 x2=-4
2)x^2−3x+2=0
Решение:x^2-3x+2=x^2-2x-x+2=x(x-2)-(x-2)=(x-1)(x-2)x 2−3x+2=x 2−2x−x+2=x(x−2)−(x−2)=(x−1)(x−2)
x1=1 x2=2