Составьте уравнение касательной к графику функции y = – x2

zmudtroman7 @zmudtroman7

June 2022 1 6 Report

Составьте уравнение касательной к графику функции y = – x2 – 4x + 2 , проходящей через точку М(-3;5)

Answers & Comments

NNNLLL54

Verified answer

Ответ:

$y=-x^2-4x+2\ \ ,\ \ \ M(-3\ ;\ 5\ )\\\\y(M)=y(-3)=-(-3)^2-4\cdot (-3)+2=5\\\\y'(x)=-2x-4\ \ ,\ \ y(-3)=6-4=2\\\\kasatelnaya:\ \ y=5+2(x+3)\\\\{}\qquad \qquad \quuad \qquad \ \ \boxed {\ y=2x+11\ }$

1 votes Thanks 1

reshite zadachu v gruppe 10 yunoshej i 8 devushek nuzhno vybrat delegaciyu iz dvuh chel

Answer

zmudtroman7 June 2022 | 0 Ответы

reshite zadachu obrazuyushaya konusa ravna 12 sm i naklonena k ploskosti osnovaniya p

Answer

Answers & Comments

Verified answer

reshite srochnopzhpzhpzhpzhzhpzhpzhzhzhpzhpzhpzhpzh

reshite srochno ppzhzhpzhpzhpzhpzhpzhpzhpzhpzhpzhpzhzhpzh

reshite zadachu skolkimi sposobami mozhno zapolnit loterejnyj bilet 5 iz 36

vychislite ploshad figury ogranichennoj liniyami u1 h 2 u h 1

vychislite obem cilindricheskoj emkosti esli eyo vysota 6 m a diametr 2 m

reshite zadachu v gruppe 10 yunoshej i 8 devushek nuzhno vybrat delegaciyu iz dvuh chel

reshite zadachu obrazuyushaya konusa ravna 12 sm i naklonena k ploskosti osnovaniya p

рекомендуемые вопросы

Helpful Links

Helpful Social