Ответ:
дано
m(Zn) = 196 g
----------------
V(H2)-?
Zn+H2SO4-->ZnSO4+H2
M(Zn) = 65 g/mol
n(Zn) = m/M = 196 / 65 = 3,015 mol
n(Zn) = n(H2)
V(H2) = n*Vm = 3.015 * 22.4 = 67.536 L
ответ 67.536 л
Объяснение:
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Answers & Comments
Ответ:
дано
m(Zn) = 196 g
----------------
V(H2)-?
Zn+H2SO4-->ZnSO4+H2
M(Zn) = 65 g/mol
n(Zn) = m/M = 196 / 65 = 3,015 mol
n(Zn) = n(H2)
V(H2) = n*Vm = 3.015 * 22.4 = 67.536 L
ответ 67.536 л
Объяснение: