Ответ:
дано
m(H2SO4) = 490 g
---------------------
m(Ba(OH)2)- - ?
H2SO4+Ba(OH)2-->BaSO4+2HOH
M(H2SO4) = 98 g/mol
n(H2SO4)= m/M = 490 / 98 = 5 mol
n(H2SO4) = n(BaSO4)
M(Ba(OH)2 = 171 g/moL
m(Ba(OH)2) = n*M =5*171 =855 g
ответ 855 г
Объяснение:
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Ответ:
дано
m(H2SO4) = 490 g
---------------------
m(Ba(OH)2)- - ?
H2SO4+Ba(OH)2-->BaSO4+2HOH
M(H2SO4) = 98 g/mol
n(H2SO4)= m/M = 490 / 98 = 5 mol
n(H2SO4) = n(BaSO4)
M(Ba(OH)2 = 171 g/moL
m(Ba(OH)2) = n*M =5*171 =855 g
ответ 855 г
Объяснение: