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maksus1wolf
@maksus1wolf
July 2022
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Ставлю 100 баллов
решить уравнение,очень срочно √(1-3sin6x)=-2*(√2)*cos3x
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o1l7eg17
7cos3x-sin3x=0 sin3x+cos3x=0
7cos3x=sin3x sin3x=-cos3x
7ctg3x=1 tg3x=-1
ctg3x=1/7 3x=-π/4 +πn; n∈Z
3x=arcctg(1/7)+πn;n∈Z x=πn/3 -π/12; n∈Z
x=(1/3)arcctg(1/7)+(πn/3
); n∈Z
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Answers & Comments
7cos3x-sin3x=0 sin3x+cos3x=0
7cos3x=sin3x sin3x=-cos3x
7ctg3x=1 tg3x=-1
ctg3x=1/7 3x=-π/4 +πn; n∈Z
3x=arcctg(1/7)+πn;n∈Z x=πn/3 -π/12; n∈Z
x=(1/3)arcctg(1/7)+(πn/3); n∈Z