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stetkhem67
@stetkhem67
August 2021
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Сумма трех первых членов равна 6,первый член равен 5.Найдите третий член и разность прогрессии.
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ludmilagena
Verified answer
A1=5
a2=a1+d
a3 = a2+d=a1+2d
a1+a2+a3 =a1+(a1+d)+(a1+2d) = 3a1 +3d =3*5 +3d=15+3d
15+3d = 6
3d = 6-15
d= - 3
a2= 5-3=2
a3=2-3=-1
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Answers & Comments
Verified answer
A1=5a2=a1+d
a3 = a2+d=a1+2d
a1+a2+a3 =a1+(a1+d)+(a1+2d) = 3a1 +3d =3*5 +3d=15+3d
15+3d = 6
3d = 6-15
d= - 3
a2= 5-3=2
a3=2-3=-1