tex] -12x-59

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August 2022 2 18 Report

Решите,пожалуйста.Подробно.

1. -2(4-x)≤-1-5x

2. 2[tex] x^{2} [/tex] -12x-59<-3[tex] x^{2} -5x-25

ВладимирБ

Verified answer

Решение смотри в приложении

1 votes Thanks 1

wangross 1)
$-2(4-x) \leq -1-5x \\ -8+2x \leq -1-5x \\ 2x+5x \leq -1+8 \\ 7x \leq 7 \\ x \leq 1$

Ответ: $x\in(-\infty;1]$

2)
$2 x^{2} -12x-59\ \textless \ -3x^2-5x-25 \\ 2 x^{2} +3 x^{2} -12x+5x-59+25\ \textless \ 0 \\ 5x^2-7x-34\ \textless \ 0 \\ 5x^2-7x-34=0 \\ D=49-4*5*(-34)=49+680=729=27^2 \\ \\ x_1= \frac{7+27}{10}= \frac{34}{10}=3,4~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~x_2= \frac{7-27}{10}=- \frac{20}{10}=-2 \\ \\5x^2-7x-34\ \textless \ 0 \\ ( x+2)(x-3,4)\ \textless \ 0$

_____+____ $-2$ _____-_____ $3,4$ _____+_____

Ответ: $x\in(-2;~3,4)$

0 votes Thanks 1

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