пожалуйста, решите неравенство!!!!
2log2((x+2)/(x-3.7))+log2(x-3.7)^2[tex] \geq [/tex] 2
2log2((x+2)/(x-3.7))+log2(x-3.7)^2[tex] \geq [/tex] 2
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ОДЗ(x+2)/(x-3,7)>0
x=-2 x=3,7
x<-2 U x>3,7
x-3,7>0
x>3,7
x∈(3,7;∞)
log(2)[(x+2)²/(x-3,7)²*(x-3,7)²]≥2
log(2)(x+2)²≥2
(x+2)²≥4
(x+2)²-4≥0
(x+2-2)(x+2+2)≥0
x(x+4)≥0
x=0 x=-4
x≤-4 U x≥0 +ОДЗ
x∈(3,7;∞)