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fisovich
@fisovich
June 2023
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Решите неравенство:
а) [tex]x^2-49\ \textgreater \ 0;[/tex]
б) [tex]x^2+6x\ \textless \ 0;[/tex]
в) [tex]2x^2-x-6 \leq 0;[/tex]
г) [tex]x^2-6x+9\leq 0;[/tex]
д) [tex]\frac{x^2}{5}+\frac{2x}{3}\geq \frac{8}{15}.[/tex]
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aruzhan6928
Если не правильно то прости я сделала что смогла
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