Ответ:
x = [tex]\frac{\pi }{3} + \frac{\pi n}{2}[/tex]
Объяснение:
[tex]tg(2x - \frac{\pi }{3} ) = \sqrt{3} \\- > x \neq \frac{5\pi }{12} + \frac{\pi n}{2}\\ 2x - \frac{\pi }{3} = \frac{\pi }{3} + \pi n\\x = \frac{\pi }{3} + \frac{\pi n}{2}[/tex]
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Ответ:
x = [tex]\frac{\pi }{3} + \frac{\pi n}{2}[/tex]
Объяснение:
[tex]tg(2x - \frac{\pi }{3} ) = \sqrt{3} \\- > x \neq \frac{5\pi }{12} + \frac{\pi n}{2}\\ 2x - \frac{\pi }{3} = \frac{\pi }{3} + \pi n\\x = \frac{\pi }{3} + \frac{\pi n}{2}[/tex]