Знайдіть похід функції :
[tex]f(x) = x + \sin \: x[/tex]
[tex]f(x) = {x}^{2} (x - 3)[/tex]
[tex]f(x) = x + \sin \: x[/tex]
[tex]f(x) = {x}^{2} (x - 3)[/tex]
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Ответ:
Объяснение:
f'(x)=(x+sinx)'=1+cosx
f'(x)=(x²(x-3))'=(x²)'(x-3)+x²(x-3)'=2x(x-3)+x²=2x²-6x+x²=3x(x-2)