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pu76396
@pu76396
July 2023
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[tex]( \frac{ \sin \alpha }{ \sin4 \alpha } + \frac{ \cos\alpha }{ \cos4 \alpha } ) \times \frac{ \cos {}^{2}2 \alpha - \sin ^{2}2 \alpha }{ \sin5 \alpha } [/tex]
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