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frozensupra
@frozensupra
July 2022
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Вычислите значение выражения [tex] \frac{a^2-b^2}{a-b}- \frac{a^3-b^3}{a^2-b^2} [/tex], если a = 10,3; b = -0,3
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Vas61
(a-b)(a+b)/(a-b)-(a-b)(a²+ab+b²)/(a-b)(a+b)=(a+b)-(a²+ab+b²)/(a+b)=[(a+b)²-(a²+ab+b²)]/(a+b)=(a²+2ab+b²-a²-ab-b²)/(a+b)=ab/(a+b)=10,3×(-0,3)/(10,3-0,3)=-3,09/10=-0,309
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