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frozensupra
@frozensupra
August 2022
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Найти точки разрыва функции и провести их классификацию.
[tex]f(x) = \frac{6x^{2}-x-7 }{x^{2} -x-2}[/tex]
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армения20171
F(x)=(6x²-x-7)/(x²-x-2)
точки разрыва
х²-х-2=0
Д=1+8=9=3²
х=(1±3)/2
х1=2;х2=-1
этих точки разрыва
второй степени
lim((6x²-x-7)/(x²-x-2)=
lim6(x+1)(x-7/6)/(x-2)((x+1)=
lim6(x-7/6)/(x-2)
lim(6x²-x-7)/(x²-x-2)=
lim(1+5(x²-1)/(x-2)((x+1))=
lim(1+5(x-1)/(x-2))=
lim(1+5(x-2+1)/(x-2)=
lim(1+5+5/(x-2))=
lim(6+5/(x-2))
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Answers & Comments
точки разрыва
х²-х-2=0
Д=1+8=9=3²
х=(1±3)/2
х1=2;х2=-1
этих точки разрыва
второй степени
lim((6x²-x-7)/(x²-x-2)=
lim6(x+1)(x-7/6)/(x-2)((x+1)=
lim6(x-7/6)/(x-2)
lim(6x²-x-7)/(x²-x-2)=
lim(1+5(x²-1)/(x-2)((x+1))=
lim(1+5(x-1)/(x-2))=
lim(1+5(x-2+1)/(x-2)=
lim(1+5+5/(x-2))=
lim(6+5/(x-2))