[tex]lg \sqrt[3]{ 2^{4x-1} } = - lg(0,125) [/tex] В ответ запишите [tex]10 x_{0} - 20[/tex], где[tex] x_{0} [/tex] корень уравнения
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lg∛2⁴ˣ⁻¹=lg(0,125)⁻¹
∛2⁴ˣ⁻¹=1000/125
∛2⁴ˣ⁻¹=(10/5)³
2⁴ˣ⁻¹=(2³)³
2⁴ˣ⁻¹=2⁹
4x-1=9
4x=9+1
4x=10
x=10/4=2,5
10*2,5-20=25-20=5