[tex](x+1)^4+(x+1)^2 -6 =0[/tex] Помогите пожалуйста :з. Created by Shadynew. matematika-ru

tex] Помогите пожалуйста :з...

Shadynew @Shadynew

August 2022 1 6 Report

[tex](x+1)^4+(x+1)^2 -6 =0[/tex]

Помогите пожалуйста :з

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KuOV

Verified answer

(x + 1)² = t
t² + t - 6 = 0
D = 1 + 24 = 25
t = (- 1 - 5)/2 = - 3 t = (- 1 + 5)/2 = 2
(x + 1)² = - 3 (x + 1)² = 2
нет корней x + 1 = √2 x + 1 = - √2
x = √2 - 1 x = -√2 - 1

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