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Shadynew
@Shadynew
July 2022
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Комплексные числа
z=z₁/z₂+z₃
z₁=-3-2i
z₂=1+9i
z₃=-6+i
z=?
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DonPedro80
(-3-2i)/(1+9i)=(-3-2i)(1-9i)/[(1-9i)(1+9i)]=(-21+25i)/82
(-21+25i)/82+(-6+i)=(-513+107i)/82
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Answers & Comments
(-21+25i)/82+(-6+i)=(-513+107i)/82