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Shadynew
@Shadynew
July 2022
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Здрасте)
Помогите, а то я не догоняю.
4√3(4-х)>7(4-х)
Заранее спасибо))
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sedinalana
Verified answer
4√3(4-x)-7(4-x)>0
(4-x)(4√3-7)>0
4√3-7<0⇒4-x<0
x>4
x∈(4;∞)
1 votes
Thanks 1
Shadynew
Спасибо тебе, хоспади, ты спасла меня
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Answers & Comments
Verified answer
4√3(4-x)-7(4-x)>0(4-x)(4√3-7)>0
4√3-7<0⇒4-x<0
x>4
x∈(4;∞)