[tex]0,125*2^{4x-16} = (\frac{0.25}{\sqrt{2}})^{-x} [/tex]
решите пожалуйстааа
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[tex]0,125*2^{4x-16} = (\frac{0.25}{\sqrt{2}})^{-x} [/tex]
решите пожалуйстааа
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0,125*2^(4x-16)=(0,25/sqrt2)^(-x)
2^(-3)*2^(4x-16)=(4*sqrt2)^x
2^(4x-19)=2^(2,5x)
4x-19=2,5x
1,5x=19
x=19*(2/3)
x=38/3
x=12,(6)